如何不用sleep实现线程同步?不使用sleep的话,pthread_cond_wait
如何不用sleep实现线程同步?
不使用sleep的话,pthreadcondwait(&transformed, &lock)还未执行,transform信号就先发出了,就没有用了
如何不用sleep,尽量不用pause,使pthreadcondwait(&transformed, &lock)执行?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/types.h>
#include <signal.h>
#include <pthread.h>
void *sender(void *);
void *receiver(void *);
char msg[60];
int tfed;
pthread_mutex_t lock = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t inputed = PTHREAD_COND_INITIALIZER;
pthread_cond_t transformed = PTHREAD_COND_INITIALIZER;
int main(int argc, char **argv) {
int err; void *sent;
pthread_t sthd, rthd;
err = pthread_create(&rthd, NULL, receiver, NULL);
err = pthread_create(&sthd, NULL, sender, NULL);
if (err != 0) {
fprintf(stderr, "can't create sender thread: %s\n", strerror(err));
exit(1);
}
pthread_join(sthd, &sent);
pthread_join(rthd, &sent);
pthread_mutex_destroy(&lock);
pthread_cond_destroy(&inputed);
pthread_cond_destroy(&transformed);
printf("Sent Messsages %d\n", (int)sent);
}
void *sender(void *arg){
FILE *fp;
char line[132], output[132];
int sent_msg=0, sender_pid;
while (1) {
pthread_mutex_lock(&lock);
fgets(msg, sizeof(msg), stdin);
pthread_mutex_unlock(&lock);
pthread_cond_signal(&inputed);
sent_msg++;
if (strcmp(line, "end\n") == 0) break;
pthread_mutex_lock(&lock);
pthread_cond_wait(&transformed, &lock);
printf("Output msg:%s\n", msg);
pthread_mutex_unlock(&lock);
}
pthread_exit((void *)sent_msg);
}
void *receiver(void *arg){
FILE *fp;
char line[132], output[132];
int sent_msg=0, i;
while(1){
pthread_mutex_lock(&lock);
pthread_cond_wait(&inputed, &lock);
strcpy(line, msg);
if (strcmp(msg, "end\n") == 0) break;
for(i=0;i<strlen(line);i++) msg[i]= toupper(line[i]);
msg[i]='\0';
strcpy(output, msg);
pthread_mutex_unlock(&lock);
//printf("Transformed msg:%s\n", output);
sent_msg++;
sleep(1);
pthread_cond_signal(&transformed);
}
pthread_exit((void *)sent_msg);
}
史库水不是水
14 years, 11 months ago
Answers
当消费者从生产者那里取走了货物,并使用后,生产者才能再生产
如果我没有理解错,你想表达这样的意思,那么多线程的意义何在呢?
要实现你的代码,需要增加标志,表示信号是否已经发出,比如,a 等待 b的信号
a {
pthread_mutex_lock(&lock);
if (sended == 0) {
pthread_cond_wait(&sig, &lock);
}
pthread_mutex_unlock(&lock);
}
b {
pthread_mutex_lock(&lock);
sended = 1;
pthread_cond_signal(&sig);
pthread_mutex_unlock(&lock)
}
zhainan
answered 14 years, 11 months ago