Answers
其实就是百度转火星坐标
public static double[] bd2gcj(double[] locs) {
double x = locs[1] - 0.0065, y = locs[0] - 0.006;
double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);
double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);
locs[1] = z * Math.cos(theta);
locs[0] = z * Math.sin(theta);
return locs;
}
收图的小偷
answered 10 years, 10 months ago