方法1：

dictMerged1=dict(dict1.items()+dict2.items())

方法2：

dictMerged2=dict(dict1, **dict2)

方法2等同于：

dictMerged=dict1.copy()
dictMerged.update(dict2)

或者：

dictMerged=dict(dict1)
dictMerged.update(dict2)

方法2比方法1速度快很多，用timeit测试如下

$ python -m timeit -s 'dict1=dict2=dict((i,i) for i in range(100))' 'dictMerged1=dict(dict1.items()+dict2.items())'
10000 loops, best of 3: 20.7 usec per loop

$ python -m timeit -s 'dict1=dict2=dict((i,i) for i in range(100))' 'dictMerged2=dict(dict1,**dict2)'
100000 loops, best of 3: 6.94 usec per loop

$ python -m timeit -s 'dict1=dict2=dict((i,i) for i in range(100))' 'dictMerged3=dict(dict1)' 'dictMerged3.update(dict2)'
100000 loops, best of 3: 7.09 usec per loop

$ python -m timeit -s 'dict1=dict2=dict((i,i) for i in range(100))' 'dictMerged4=dict1.copy()' 'dictMerged4.update(dict2)'
100000 loops, best of 3: 6.73 usec per loop