平衡二叉树DSW算法的实现?
//DSW Algorithm
//我先放二叉树的定义上来,代码丑陋,不要见怪。
#ifndef BSTREE_H_
#define BETREE_H_
///////////////////////////////////////////////////////////////
//
// File: BSTree.h
//
// This headfile defines BST class to test BSTree.
//
// By tankeryang.
//
// 2015, Dec 2
//
///////////////////////////////////////////////////////////////
#include<iostream>
#include<queue>
#include<stack>
using namespace std;
template<class T>
class Stack:public stack<T>{};
template<class T>
class Queue:public queue<T>{
public:
T dequeue(){
T tmp = front();
queue<T>::pop();
return tmp;
};
void enqueue(T item){
push(item);
};
};
class BSTNode{
public:
int item;
BSTNode *lchild, *rchild;
int level;
BSTNode(){
lchild = rchild = NULL;
};
BSTNode(int i){
item = i;
lchild = rchild = NULL;
};
};
class BSTree:public BSTNode{
protected:
BSTNode *root;
int countOfNode;
int levelOfTree;
public:
BSTree(){
root = NULL;
countOfNode = 0;
levelOfTree = 0;
};
~BSTree(){};
int getLevelOfTree();
void insert(int);
void breadthFirst();
//DSW algorithm
void rotateRight(BSTNode *);
void creatBackbone();
void creatPerfectTree();
//Inorder recurrence algorithm
void inOrder();
void inRecurrence(BSTNode *);
//////
void visit(BSTNode *node) {
std::cout << node->item << ' ';
};
};
#endif
//接下来放DSW的三个函数的定义
//调试的时候,会出现死循环,原因是出在rotateRight(BSTNode *)
//函数,可能判断条件有问题,还有下面的creatPerfectTree()也有问
//题,望高手赐教。要是觉得在下代码实现的太烂,希望能详细说说您的
//理解,不胜感激。
// DSW Algorithm
void BSTree::rotateRight(BSTNode *pnode){
// Rotate the left node to the right link list.
if(pnode->lchild != NULL) {
BSTNode *tmp = pnode->lchild;
pnode->lchild = tmp->rchild;
tmp->rchild = pnode;
pnode = tmp;
}
else if (pnode->lchild == NULL && pnode->rchild->lchild != NULL) {
BSTNode *flag = pnode;
pnode = pnode->rchild;
BSTNode *tmp = pnode->lchild;
pnode->lchild = tmp->rchild;
tmp->rchild = pnode;
flag->rchild = tmp;
pnode = flag->rchild;
}
else
pnode = pnode->rchild;
};
void BSTree::creatBackbone(){
BSTNode *pnode = root;
while(pnode!=NULL)
rotateRight(pnode);
};
void BSTree::creatPerfectTree(){
BSTNode *tmp1=root, *tmp2=tmp1->rchild->rchild;
while(tmp1!=NULL){
if(tmp2!=NULL && tmp2->rchild!=NULL){
tmp1->rchild = tmp1->rchild->lchild;
tmp1->rchild->lchild = tmp1;
tmp1 = tmp1->rchild;
tmp1->rchild = tmp1->rchild->rchild;
tmp2->rchild->lchild = tmp2;
tmp2->rchild = NULL;
tmp2 = tmp1->rchild->rchild;
}
else
break;
}
};
baga10
9 years, 3 months ago