php文件里js不能被执行
我想把上传文件路径返回到前端保存,但是后台php文件里的js没有执行,前台input标签里的value值一直为空
后台acceptfile.php代码如下:
<?php if(!isset($_REQUEST['filename'])) { exit('No file'); } else{ $upload_path = dirname(__FILE__).'/audio'; date_default_timezone_set("Asia/Shanghai"); $filename = $_REQUEST['filename'].rand(0,10000).date('YmdHis'); $fp = fopen($upload_path."/".$filename.".wav", "wb"); $audiosrc=$upload_path."/".$filename.".wav"; echo "<script language='javascript'>parent.send_form.audiosrc.value='$audiosrc';</script>"; echo "<script language='javascript'>alert('上传成功');</script>"; fwrite($fp, file_get_contents('php://input')); fclose($fp); exit('done'); } ?>
前端index.php里form表单:
<form id="send_form" method="post" enctype="multipart/form-data"> ... <input type="hidden" name="audiosrc" id="audiosrc" value="" /> <input type="submit" class="send" id="send" value="提交"> </form>
请问问题出在哪,文件是有保存到相应的文件夹里的,就是路径没法返回到前端form表单里
NEET面瘫
11 years, 7 months ago