Answers
参: @僵尸进程问题
1：如何产生:
僵尸进程，子进程先于父进程结束，而父进程未用wait或waitpid来监听子进程的状态，使子进程的资源无法释放。
孤儿进程：父进程先于子进程结束。
2：作用
僵尸进程：几乎没有什么作用，像
@浪际天涯
提到的一样，不会被调度。
孤儿进程：最经典的一个作用应该是避免产生僵尸进程，通过fork两次的方式，刻意杀掉其父进程，使之成为守护进程。
3：如何杀死僵尸进程
copy
@浪际天涯
4：杀死僵尸进程的shell脚本
再提供一个网络版本:
Automatic “zombie” processes killing (shell script)
#!/bin/bash
# Zombie processes killing script.
# Must be run under root.
case "$1" in
--admin)
stat=`ps ax | awk '{print $1}' | grep -v "PID" | xargs -n 1 ps lOp | grep -v "UID" | awk '{print"pid: "$3" *** parent_pid: "$4" *** status: "$10" *** process: "$13}' | grep ": Z"`
if ((${#stat} > 0));then
echo zombie processes found:
echo .
ps ax | awk '{print $1}' | grep -v "PID" | xargs -n 1 ps lOp | grep -v "UID" | awk '{print"pid: "$3" *** parent_pid: "$4" *** status: "$10" *** process: "$13}' | grep ": Z"
echo -n "Kill zombies? [y/n]: "
read keyb
if [ $keyb == 'y' ];then
echo killing zombies..
ps ax | awk '{print $1}' | grep -v "PID" | xargs -n 1 ps lOp | grep -v "UID" | awk '{print$4" status:"$10}' | grep "status:Z" | awk '{print $1}' | xargs -n 1 kill -9
fi
else
echo no zombies found!
fi
;;
--cron)
stat=`ps ax | awk '{print $1}' | grep -v "PID" | xargs -n 1 ps lOp | grep -v "UID" | awk '{print"pid: "$3" *** parent_pid: "$4" *** status: "$10" *** process: "$13}' | grep ": Z"`
if ((${#stat} > 0));then
ps ax | awk '{print $1}' | grep -v "PID" | xargs -n 1 ps lOp | grep -v "UID" | awk '{print$4" status:"$10}' | grep "status:Z" | awk '{print $1}' | xargs -n 1 kill -9
echo `date`": killed some zombie proceses!" >> /var/log/zombies.log
fi
;;
*) echo 'usage: zombies {--cron|--admin}'
;;
esac
exit 0
卡特蕾亚大死机
answered 12 years, 10 months ago
