jackson 序列化一个类怎么能生成多种JSON
javapublic class Board { private Integer boardId; private Integer userId; private String title; private String description; private String categoryId; private int seq; private long pinCount; private long followCount; private long likeCount; private long createdAt; private long updatedAt; private int deleting; private int isPrivate; private Object extra; private List<Pin> pins; private User user; }
比如上面
Board
类
格式一：
json
:
json{ "board_id": 18523725, "user_id": 12314505, "title": "室内软装之儿童房", "description": "", "category_id": "home", "seq": 18523725, "pin_count": 153, "follow_count": 81, "like_count": 7, "created_at": 1416270907, "updated_at": 1419990698, "deleting": 0, "is_private": 0, "extra": null, "pins": [], "user": {} }
格式二：
json
:
json{ "board_id": 18523725, "user_id": 12314505, "title": "室内软装之儿童房", "description": "", "category_id": "home", "seq": 18523725, "pin_count": 153, "follow_count": 81, "like_count": 7, "created_at": 1416270907, "updated_at": 1419990698, "deleting": 0, "is_private": 0 }
格式三：
json
:
json{ "board_id": 18523725, "user_id": 12314505, "title": "室内软装之儿童房", "description": "", "category_id": "home" }
等等。。。
琐琐碎碎2
10 years, 4 months ago
Answers
通过
filter
过滤字段可以达到这个目的
ObjectMapper mapper = new ObjectMapper();
// Exclude Null Fields
mapper.setSerializationInclusion(Inclusion.NON_NULL);
String[] ignorableFieldNames = { "pins", "user" };
FilterProvider filters = new SimpleFilterProvider()
.addFilter("filter Board",SimpleBeanPropertyFilter.serializeAllExcept(ignorableFieldNames));
ObjectWriter writer = mapper.writer(filters);
System.out.println(writer.writeValueAsString(new Board()));
无所不在的大海
answered 10 years, 4 months ago