Question

0 0

Crontab每个月的倒数第七天执行怎么写？
我在stackoverflow上查到倒数第一天执行的写法:


 55 23 30 4,6,9,11        * myjob.sh
55 23 31 1,3,5,7,8,10,12 * myjob.sh
55 23 28 2               * myjob.sh

有没有简单一点的？

10 years, 3 months ago

share

Mcstar 10 years, 3 months ago

Answer 1

0

每天执行，在shell脚本里判断今天是不是倒数第7天
本月有多少天可以用
cal $(date +"%m %Y") | awk 'NF {DAYS = $NF}; END {print DAYS}'

answered 10 years, 3 months ago

share

板野友美· answered 10 years, 3 months ago